Question

Чему равен коэффициент трения, если автомобиль, имеющий скорость 20 м/с, после резкого торможения прошел 50 м до полной остановки за 5 с?​

Answer 1

Ответ:

0,2

Объяснение:

v=20м/с;

S=50м;

t=5с;

μ-?;

s=vt-at^2/2; a=2(vt-s)/t^2;

Fтр=μmg;

Fтр=ma;

μmg=2m(vt-s)/t^2;

μ=2(vt-s)/(t^2g);

μ=2*(20м/с*5с-50м)/(25*10н/кг)=0,2

Answer 2

Calculation of the Coefficient of Friction

To calculate the coefficient of friction, we can use the equation:

Coefficient of Friction = (Deceleration) / (Acceleration due to gravity)

To find the deceleration, we can use the equation:

Deceleration = (Final Velocity - Initial Velocity) / Time

Given: - Initial velocity (v0) = 20 m/s - Distance traveled (S1) = 50 m - Time taken (t) = 5 s

Let's calculate the deceleration first:

Deceleration = (0 - 20) / 5 = -4 m/s^2

Now, let's calculate the coefficient of friction:

Coefficient of Friction = (-4) / (9.8) ≈ -0.41

Therefore, the coefficient of friction is approximately -0.41.