Question

Пружина жёсткость 200Н на метр с грузом 4кг поднимается с ускорением 2м/с. Определить растяжение пружины

Answer 1

Дано:

k = 200 Н/м

m = 4 кг

a = 2 м/с²

Найти:

Δl - ?

Объяснение:

(Если пренебречь ускорением свободного падения и силой сопротивления воздуха)

F = ma = 4 * 2 = 8 Н

F = kΔl ----> Δl = F/k = 8 / 200 = 0.04 м

Answer 2

Calculation of Spring Extension

To determine the extension of the spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement or extension of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force exerted by the spring, - k is the spring constant (also known as stiffness or rigidity), and - x is the displacement or extension of the spring.

In this case, we are given the following information: - Spring constant (k) = 200 N/m - Mass of the load (m) = 4 kg - Acceleration (a) = 2 m/s²

To find the extension of the spring, we need to calculate the force exerted by the spring. We can do this by multiplying the mass of the load by the acceleration:

F = m * a

F = 4 kg * 2 m/s²

F = 8 N

Now, we can use Hooke's Law to find the extension of the spring:

F = k * x

8 N = 200 N/m * x

Solving for x:

x = 8 N / 200 N/m

x = 0.04 m

Therefore, the extension of the spring is 0.04 meters.