Question

Два груза массами m1 = 400 г и m2 = 200 г связаны невесомой нерастяжимой нитью, рассчитанной на предельную нагрузку F = 8,20 H. Определите модуль максимальной силы F, с которой можно тянуть груз массой m1 по гладкой горизонтальной поверхности, чтобы нить не порвалась. Обьясните плз, именно полное нормальное обьяснение. сухие формулы есть и так в решебе, я хочу разобраться, поэтому даю много баллов​

Answer 1

Ответ:

24.6 H

Объяснение:

m1=0.4 кг     m2=0.2 кг    F=8.2 H    Fm=?

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Сила максимальная для двух масс:

Fm=(m1+m2)*a

Оба тела движутся с одинаковым ускорением а.

Второе тело под действием силы F движется

F=m2*a  ----> a=F/m2

Fm=(m1+m2)*F/m2=(0.4+0.2)*8.2/0.2=24.6 H

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Answer 2

Calculation of the Maximum Tension Force on the String

To determine the maximum tension force with which the string can be pulled without breaking, we need to consider the forces acting on the system.

Let's assume that the tension force in the string is denoted by T.

The system consists of two masses, m1 and m2, connected by an inextensible string. The tension force T acts on both masses.

Since the masses are connected by a string, the tension force T is the same for both masses.

The forces acting on m1 are: - The weight force F1 = m1 * g, where g is the acceleration due to gravity.

The forces acting on m2 are: - The weight force F2 = m2 * g.

Since the system is in equilibrium, the sum of the forces acting on each mass must be zero.

For m1: - T - F1 = 0

For m2: - T - F2 = 0

Solving these equations simultaneously, we find that T = F1 = F2.

To find the maximum tension force F, we need to determine the maximum weight force that the string can support without breaking.

The maximum weight force is equal to the breaking strength of the string, which is given as 8.20 H.

Therefore, F = 8.20 H.

Conclusion

The maximum tension force with which the string can be pulled without breaking is 8.20 H.

Please note that the provided search results did not provide specific formulas or calculations for this particular problem. However, the explanation provided above is based on the principles of equilibrium and the assumption that the tension force in the string is the same for both masses.