Question

Самолет пролетел 780 км за 4 часа за первый час 170 км за второй час на 26 км больше чем за первый а остальное расстояние поровну за третье и четвёртое часы с какой скоростью летел самолёт в последние два часа

Answer 1

Ответ:

1)170+26=196(км)2 час

2)170+196=366(км)за 1 и 2 час

780-360=414(км)за 3 и 4 час

414÷2=207(км)

Answer 2

Calculation of Average Speed

To calculate the average speed of the plane during the last two hours, we need to determine the total distance traveled during those two hours and divide it by the time taken.

Given information: - Total distance traveled: 780 km - Time taken: 4 hours - Distance traveled in the first hour: 170 km - Distance traveled in the second hour: 26 km more than the first hour - Remaining distance divided equally between the third and fourth hours

Let's break down the calculation step by step:

1. Calculate the distance traveled in the second hour: - Distance traveled in the second hour = Distance traveled in the first hour + 26 km - Distance traveled in the second hour = 170 km + 26 km = 196 km

2. Calculate the remaining distance after the first two hours: - Remaining distance = Total distance - Distance traveled in the first hour - Distance traveled in the second hour - Remaining distance = 780 km - 170 km - 196 km = 414 km

3. Calculate the average speed during the last two hours: - Average speed = Remaining distance / Time taken for the last two hours - Average speed = 414 km / 2 hours = 207 km/h

Therefore, the plane flew at an average speed of 207 km/h during the last two hours.

Please note that the above calculation assumes a constant speed throughout the entire journey.