Question

2. В проводнике длиной 4 см сила тока равна 70 А. Он находится в магнитном поле с индукцией 40 мТл. Найти совершённую работу, если проводник переместился на 30 см перпендикулярно силовым линиям.​

Answer 1

Ответ:

33,6*10⁻³ Дж

Объяснение:

L=0.04 м    I=70 A     B=0.04 Тл     s=0.3 м    A=?

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A=F*s

F=I*B*L

A=I*B*L*s=70*0.04*0.04*0.3=33.6*10⁻³ Дж

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Answer 2

Calculation of Work Done by the Conductor

To calculate the work done by the conductor, we can use the formula:

Work (W) = Force (F) x Distance (d) x Cosine of the Angle (θ) between the force and displacement

In this case, the force acting on the conductor is given by the product of the current (I) and the magnetic field strength (B):

Force (F) = I x B

Given: - Length of the conductor (d) = 4 cm = 0.04 m - Current (I) = 70 A - Magnetic field strength (B) = 40 mT = 0.04 T - Distance moved by the conductor (d) = 30 cm = 0.3 m

Let's calculate the work done by the conductor.

Step 1: Calculate the force acting on the conductor. Force (F) = I x B Substituting the given values: F = 70 A x 0.04 T = 2.8 N Step 2: Calculate the angle (θ) between the force and displacement. Since the conductor is moved perpendicular to the force lines, the angle between them is 90 degrees. θ = 90 degrees

Step 3: Calculate the work done. Work (W) = F x d x cos(θ) Substituting the given values: W = 2.8 N x 0.3 m x cos(90 degrees) = 0.84 J

Therefore, the work done by the conductor is 0.84 Joules when it is moved perpendicular to the force lines.

Please let me know if you need any further assistance.