Question

в тепловом двигателе температура холодильника составляет 273 К, а температура нагревателя равна 3073 К определите максимальный возможный КПД такого двигателя (в%) ПОМОГИТЕ ПРОШУ , ПОЖАЛУЙСТА, ДАЮ 15 БАЛЛОВ<333​

Answer 1

Ответ:

91%

Объяснение:

Дано:  T1=3073 K     T2=273 K

n=?

===

n=(T1-T2)/T1=(3073-273)/273=0.91

=====================

Answer 2

Дано:

Т2 = 3073 К

Т1 = 273 К

Найти :

η - ?

Решение:

• η = ( (Т1 -  Т2) - Т1 ) 100%
• η = ( 1 - Т1/Т2 ) 100%
• η = ( 1 - $\frac{273}{3073 }$ ) 100% = 91%

Ответ: 91 %

Answer 3

To determine the maximum possible efficiency (η) of a heat engine, we can use the Carnot efficiency formula. The Carnot efficiency is given by the equation:

η = 1 - (Tc/Th)

Where: - η is the efficiency of the heat engine, - Tc is the temperature of the cold reservoir (in Kelvin), - Th is the temperature of the hot reservoir (in Kelvin).

In this case, the temperature of the cold reservoir (Tc) is 273 K, and the temperature of the hot reservoir (Th) is 3073 K.

Calculating the Maximum Possible Efficiency:

Using the Carnot efficiency formula, we can calculate the maximum possible efficiency of the heat engine:

η = 1 - (273/3073)

Calculating this expression gives us:

η ≈ 0.9116

Therefore, the maximum possible efficiency of the heat engine is approximately 91.16%.

Please note that this calculation assumes ideal conditions and does not take into account any losses or inefficiencies that may occur in real-world heat engines.

I hope this helps! Let me know if you have any further questions.