Question

Даю 110 баллов СРОНО! Электрическая лампочка включена в сеть напряжением 220 В. При прохождении заряда через спираль лампочки была совершена работа 880 Дж. Чему равен заряд, прошедший через спираль в лампочке?

Answer 1

Ответ:

Объяснение:

U = 220 B

A = 880 Дж

q - ?

=========

А = U·q

q = A / U = 880 / 220 = 4 Кл

Answer 2

Calculation of Charge Passed through the Bulb

To calculate the charge passed through the spiral in the bulb, we can use the formula:

Q = W / V

where: - Q is the charge passed through the spiral in the bulb, - W is the work done on the charge passing through the spiral, and - V is the voltage across the bulb.

In this case, the work done on the charge passing through the spiral is given as 880 J, and the voltage across the bulb is 220 V.

Substituting these values into the formula, we can calculate the charge passed through the spiral in the bulb:

Q = 880 J / 220 V

Calculating this expression gives us:

Q = 4 C

Therefore, the charge passed through the spiral in the bulb is 4 Coulombs.