Question

Под действием силы 5 М пружина может растянуться на 4 см, рассчитайте коэффициент жесткости пружины​

Answer 1

Ответ:

125 Н/м

Объяснение:

Answer 2

Calculation of the Spring Constant

To calculate the spring constant (also known as the stiffness coefficient) of a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force applied to the spring, - k is the spring constant, - x is the displacement of the spring from its equilibrium position.

In this case, we are given that a force of 5 N stretches the spring by 4 cm (or 0.04 m). We can use this information to calculate the spring constant.

F = 5 N x = 0.04 m

Substituting these values into Hooke's Law, we get:

5 N = k * 0.04 m

To solve for k, we can rearrange the equation:

k = F / x

k = 5 N / 0.04 m

Calculating this expression, we find:

k = 125 N/m

Therefore, the spring constant of the given spring is 125 N/m.