Question

Потенциальная энергия ракеты массой 0,5 т на некоторой высоте равна 400 МДж. На какую высоту поднята ракета и какова ее скорость? (принять g = 10 м/с2)

Answer 1

Ответ:

80 км. 1270 м/с

Объяснение:

крч это правильно

Answer 2

Potential Energy of the Rocket

The potential energy of the rocket can be calculated using the formula:

Potential Energy (PE) = mass * gravity * height

Given: - Mass (m) = 0.5 t = 500 kg - Potential Energy (PE) = 400 MJ = 400,000 kJ - Acceleration due to gravity (g) = 10 m/s^2

We can rearrange the formula to solve for height:

Height (h) = PE / (m * g)

Substitute the given values: Height (h) = 400,000 kJ / (500 kg * 10 m/s^2)

Calculating the height: Height (h) = 400,000 kJ / 5,000 m Height (h) = 80 meters

Velocity of the Rocket

The velocity of the rocket can be calculated using the formula for kinetic energy:

Kinetic Energy (KE) = 0.5 * mass * velocity^2

Given: - Mass (m) = 500 kg - Kinetic Energy (KE) = 400,000 kJ (since the potential energy is converted to kinetic energy at the maximum height) - Acceleration due to gravity (g) = 10 m/s^2

We can rearrange the formula to solve for velocity:

Velocity (v) = sqrt(2 * KE / m)

Substitute the given values: Velocity (v) = sqrt(2 * 400,000 kJ / 500 kg) Velocity (v) = sqrt(800 m^2/s^2) Velocity (v) = 28.28 m/s

Conclusion

Therefore, the rocket is raised to a height of 80 meters and has a velocity of 28.28 m/s.