Question

Чему равна сила действующая на пружину если ее коэфицент упругости 50 н килограммов и ее растянули от 10 до 13 см

Answer 1

Ответ:

Сила от 5Н до 6,5Н

Объяснение:

F=k*x (Формула для нахождения сили упругости)

F1=50*0,1(перевели см в м)=5Н

F2=50*0,13(перевели см в м)=6,5Н

Чтобы растянуть на 10 см нужно приложить силу в 5Н, а на 13 см нужно сили в 6,5Н.

Answer 2

Calculation of the Force Acting on the Spring

To calculate the force acting on a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. The formula for Hooke's Law is:

F = k * x

Where: - F is the force acting on the spring, - k is the spring constant (also known as the coefficient of elasticity or coefficient of stiffness), and - x is the displacement of the spring from its equilibrium position.

In this case, we are given that the spring constant (k) is 50 N/m (newtons per meter) and the spring is stretched from 10 cm to 13 cm. To calculate the force acting on the spring, we need to convert the displacement from centimeters to meters:

x = (13 cm - 10 cm) / 100 = 0.03 m

Now we can substitute the values into the formula:

F = 50 N/m * 0.03 m = 1.5 N

Therefore, the force acting on the spring is 1.5 N.