Question

Водолаз в жёстком скафандре может погружаться в море на глубину 250 м. Какое давление оказывает на скафандр вода на этой глубине? Плотность морской воды равна 1,03 г/см 3 . Ответ выразите в килопаскалях. ​

Answer 1

Ответ: 2676,3кПа

Объяснение:

Дано:

h=250м

ρ=1,03г/см³

------------------

Р-?

Р=Ратм+Ризб=101,3+ρgh=101,3+1030*10*250/1000=2676,3кПа

Answer 2

Calculating Water Pressure at 250m Depth

A diver in a hard suit can dive into the sea to a depth of 250m. We need to calculate the pressure exerted on the suit by the water at this depth. The density of seawater is given as 1.03 g/cm^3.

To calculate the pressure exerted by the water at this depth, we can use the formula:

Pressure = Density × Acceleration due to gravity × Depth

First, let's convert the density from g/cm^3 to kg/m^3: 1.03 g/cm^3 = 1030 kg/m^3

The acceleration due to gravity is approximately 9.81 m/s^2.

Now, we can calculate the pressure: Pressure = 1030 kg/m^3 × 9.81 m/s^2 × 250m

Let's calculate the pressure.