Question

8. Определите силу тока, проходящего через реостат, изготовленный из никелиновой проволоки длиной 50 м и площадью поперечного сечения 1 мм2, если напряжение на зажимах реостата равно 35 В. СРОЧНО

Answer 1

Объяснение:

L = 50 м.

S = 1 мм2.

U = 35 В.

ρ = 0,4 Ом *мм2/м.

I - ?

I = U /R - закон Ома для участка цепи.

R = ρ *L/S,

Сила тока I будет определяться формулой: I = U *S/ρ *L.

I = 35 В *1 мм2/0,4 Ом *мм2/м *50 м = 1,75А

Answer 2

Calculation of Current through the Nickel Wire Resistor

To determine the current passing through the nickel wire resistor, we can use Ohm's Law, which states that the current (I) flowing through a conductor is equal to the voltage (V) across the conductor divided by its resistance (R). Mathematically, this can be expressed as:

I = V / R

In this case, we are given the voltage across the resistor (V = 35 V) and need to find the resistance of the nickel wire.

The resistance of a wire can be calculated using the formula:

R = (ρ * L) / A

Where: - R is the resistance of the wire - ρ (rho) is the resistivity of the material (in this case, nickel) - L is the length of the wire - A is the cross-sectional area of the wire

Given that the length of the nickel wire is 50 m and the cross-sectional area is 1 mm², we can substitute these values into the formula to find the resistance.

Let's calculate the resistance first:

R = (ρ * L) / A

Substituting the given values: - ρ (resistivity of nickel) is not provided in the question, so we will use the average resistivity of nickel, which is approximately 6.99 x 10^-8 Ω·m. - L = 50 m - A = 1 mm² = 1 x 10^-6 m²

R = (6.99 x 10^-8 Ω·m * 50 m) / (1 x 10^-6 m²)

Simplifying the expression: R = 3.495 Ω

Now that we have the resistance, we can calculate the current using Ohm's Law:

I = V / R

Substituting the given values: - V = 35 V - R = 3.495 Ω

I = 35 V / 3.495 Ω

Simplifying the expression: I ≈ 10 A

Therefore, the current passing through the nickel wire resistor is approximately 10 Amperes.

Please note that the resistivity value used in this calculation is an average value and may vary depending on the specific composition and purity of the nickel wire.

Let me know if there's anything else I can help you with!