Question

Давление в водопроводе равно 1,4•105 Па. Рассчитай,с какой силой давит вода на пробку,закрывающую отверстие трубы,если площадь отверстия равна 4см2 Ответ:вода давит на пробку с силой

Answer 1

Ответ: 56Н

Объяснение:

Дано:

Р=1,4*10⁵Па

S=4cм²=0,0004м²

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F-?

F=PS=1,4*10⁵*0,0004=56Н

Answer 2

To calculate the force exerted by water on the plug, we can use the formula:

Force = Pressure x Area

Given: Pressure in the water pipe = 1.4 x 10^5 Pa Area of the plug = 4 cm^2

First, let's convert the area from cm^2 to m^2: 1 cm^2 = 0.0001 m^2

Therefore, the area of the plug in square meters is: 4 cm^2 x 0.0001 m^2/cm^2 = 0.0004 m^2

Now, we can calculate the force exerted by water on the plug: Force = Pressure x Area Force = 1.4 x 10^5 Pa x 0.0004 m^2

Calculating this, we find that the force exerted by the water on the plug is 56 N (Newton).

Please note that the above calculation assumes that the pressure is uniform across the entire area of the plug.