Question

На тело действуют две силы в право 300Н и в лево 150Н, тело проходит 20м, какая работа при этом совершена над телом ПОМОГИТЕ ПОЖАЛУЙСТА​

Answer 1

Ответ:

3 кДж

Объяснение:

F1=300 H     F2=150 H    s=20 м    A=?

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Результирующая сила

Fp=F1-F2=300-150=150 H

Работа

A=Fp*s=150*20=3000 Дж

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Answer 2

Calculation of Work Done on the Body

To calculate the work done on the body, we can use the formula:

Work = Force × Distance

Given that two forces are acting on the body, one to the right with a magnitude of 300N and one to the left with a magnitude of 150N, and the body travels a distance of 20m, we can calculate the work done on the body.

First, let's calculate the work done by the force of 300N to the right:

Work₁ = Force₁ × Distance Work₁ = 300N × 20m Work₁ = 6000J

Now, let's calculate the work done by the force of 150N to the left:

Work₂ = Force₂ × Distance Work₂ = 150N × 20m Work₂ = 3000J

Total Work Done on the Body

The total work done on the body is the sum of the work done by the individual forces. Since the force to the left is opposing the force to the right, we need to consider the direction of the forces.

The net work done on the body is given by:

Net Work = Work₁ - Work₂ Net Work = 6000J - 3000J Net Work = 3000J

Therefore, the total work done on the body as it travels 20m under the influence of these two forces is 3000 joules.