Question

два проводника сопротивлением 12и 24 ом соединены параллельно и подключены к источнику с напряжением 120 Вольт .Определите силу тока в каждом проводнике и в общей цепи.Начертите схему .Определите силу тока в цепи , если эти проводники соединить последовательно​

Answer 1

Ответ:

10A; 5A; 15A

3.33А

Объяснение:

I=U/R

I1=120/12=10A

I2=120/24=5A

Iобщ=I1+I2=10+5=15A

Если последовательно, то

Rпосл=R1+R2=36Ом

I=120/36≈3.33А

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Answer 2

Calculation of Current in Each Conductor and Total Circuit

To calculate the current in each conductor and the total circuit, we can use the formula:

I = V / R

Where: - I = current - V = voltage - R = resistance

Given: - Resistance of the first conductor, R1 = 12 ohms - Resistance of the second conductor, R2 = 24 ohms - Voltage of the source, V = 120 volts

First, let's calculate the current in each conductor:

For the first conductor: I1 = V / R1 I1 = 120 / 12 I1 = 10 amperes.

For the second conductor: I2 = V / R2 I2 = 120 / 24 I2 = 5 amperes.

Now, let's calculate the total current in the circuit when the conductors are connected in parallel:

Total current, Itotal = I1 + I2 Itotal = 10 + 5 Itotal = 15 amperes.

Circuit Diagram

Here's a simple circuit diagram for the given scenario:

``` ----------------- ----------------- | | | | | 12 ohms | | 24 ohms | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |