Question

Помогите пожалуйста, дам 100 баллов Задача 1: Розрахуйте силу тертя ковзання, яка діє на тіло, якщо коефіцієнт тертя мiж тілом і площиною, по якiй ковзає тіло 0,5. Вага тiла 10 Н. Задача 2: Дерев'яний брусок рiвномірно тягнуть за допомогою динамометра по горизонтальнiй площині. Маса бруска 2 кг. Розрахуйте коефіцієнт тертя мiж бруском та площиною. Динамометр показує силу 2 н.​

Answer 1

Ответ: 1. F=k(напишіть грецьку "мю") P= 0,5*10=5H

Объяснение: F=k(напишіть грецьку "мю")mg.  Звідки

"мю" =F/mg=2/(2*10)=0,1

Answer 2

Task 1: Calculation of Frictional Force

To calculate the frictional force acting on an object, we can use the formula:

Frictional force = Coefficient of friction × Normal force

Given: - Coefficient of friction (μ) = 0.5 - Weight of the object (W) = 10 N

To find the normal force, we can use the formula:

Normal force = Weight of the object

Substituting the given values into the formulas, we can calculate the frictional force:

Normal force = Weight of the object = 10 N

Frictional force = Coefficient of friction × Normal force = 0.5 × 10 N = 5 N

Therefore, the frictional force acting on the object is 5 N.

Task 2: Calculation of Coefficient of Friction

To calculate the coefficient of friction between the wooden block and the surface, we can use the formula:

Coefficient of friction = Frictional force / Normal force

Given: - Mass of the block (m) = 2 kg - Force measured by the dynamometer (F) = 2 N

To find the normal force, we can use the formula:

Normal force = Weight of the block

Substituting the given values into the formulas, we can calculate the coefficient of friction:

Weight of the block = mass × acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2.

Weight of the block = 2 kg × 9.8 m/s^2 = 19.6 N

Coefficient of friction = Frictional force / Normal force = F / Weight of the block = 2 N / 19.6 N ≈ 0.102

Therefore, the coefficient of friction between the wooden block and the surface is approximately 0.102.