Question

Два шарика, расположенные на расстоянии 10 см друг от друга в вакууме, имеют одинаковые отрицательные заряды 1,6 ∙ 10- 8 Кл. Вычислите силу взаимодействия зарядов. Объясните, что произойдет с силой взаимодействия шариков, если они будут находиться в керосине, диэлектрическая проницаемость которого равна 1,8.

Answer 1

Ответ:

144мкН,80мкН

Объяснение:

1.Дано:r=10 cm=0.1m F=k×q²/r²=9×10^(9)×(1.6×10^(-8))

q1=q2=1.6×10^(-8) Kl ÷0.1²=0.000144 H=144 mkH

k=9×10^(9)

F=?

2.F=k×q²/r²×е(епсилон)=0.00000144/0.01×1.8=0.00008=80 мкН

Answer 2

Calculation of the Interaction Force between Charged Spheres

To calculate the interaction force between two charged spheres, we can use Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Given: - Two spheres with a distance of 10 cm (0.1 m) between them. - Both spheres have the same negative charge of -1.6 × 10^-8 C.

Using Coulomb's law, the formula to calculate the force (F) is:

F = (k * q1 * q2) / r^2

Where: - F is the force of interaction between the spheres. - k is the electrostatic constant, approximately equal to 9 × 10^9 Nm^2/C^2. - q1 and q2 are the charges of the spheres. - r is the distance between the centers of the spheres.

Substituting the given values into the formula:

F = (9 × 10^9 Nm^2/C^2) * (-1.6 × 10^-8 C) * (-1.6 × 10^-8 C) / (0.1 m)^2

Calculating the force using the given values:

F = 2.304 × 10^-3 N

Therefore, the force of interaction between the charged spheres in a vacuum is approximately 2.304 × 10^-3 N.

Effect of Dielectric Medium on the Interaction Force

If the spheres are placed in a dielectric medium, such as kerosene, the presence of the medium affects the interaction force between the spheres. The dielectric medium changes the effective permittivity (ε) of the space between the spheres.

The permittivity of a medium is a measure of how much the medium can reduce the electric field between charged objects. In this case, the dielectric constant (k) of kerosene is given as 1.8.

The formula to calculate the force of interaction between the spheres in a dielectric medium is:

F = (k * k0 * q1 * q2) / (r^2)

Where: - F is the force of interaction between the spheres. - k is the dielectric constant of the medium. - k0 is the electrostatic constant, approximately equal to 9 × 10^9 Nm^2/C^2. - q1 and q2 are the charges of the spheres. - r is the distance between the centers of the spheres.

Substituting the given values into the formula:

F = (1.8) * (9 × 10^9 Nm^2/C^2) * (-1.6 × 10^-8 C) * (-1.6 × 10^-8 C) / (0.1 m)^2

Calculating the force using the given values:

F = 4.1472 × 10^-3 N

Therefore, the force of interaction between the charged spheres in kerosene (with a dielectric constant of 1.8) is approximately 4.1472 × 10^-3 N.

Please note that the force of interaction between the spheres increases when they are placed in a dielectric medium compared to when they are in a vacuum.