Question

75 БАЛЛОВ Пружина динамометра под действием силы 1Н удлинилась на 2 мм. Если к этому динамометру подвесить медный шар, то пружина удлинится на 5мм. Чему равен объем шара? "Ответ 28 см^3, но мне нужно решение, пожалуйста"

Answer 1

Ответ: 28 см³, решение  на фото

Объяснение:

Answer 2

To find the volume of the copper sphere, we can use the information given about the extension of the spring in two different scenarios.

Let's denote the original length of the spring as L and the extension of the spring when a force of 1N is applied as ΔL1 = 2mm. When the copper sphere is hung from the dynamometer, the extension of the spring becomes ΔL2 = 5mm.

We can use Hooke's Law, which states that the extension of a spring is directly proportional to the force applied to it, to set up an equation:

F = k * ΔL

Where F is the force applied, k is the spring constant, and ΔL is the extension of the spring.

In the first scenario, when a force of 1N is applied, we have:

1N = k * 2mm

In the second scenario, when the copper sphere is hung, we have:

1N = k * 5mm

Dividing the second equation by the first equation, we can eliminate the spring constant:

(1N / k * 5mm) = (k * 2mm) / (k * 5mm)

Simplifying the equation, we get:

1 / 5 = 2 / 5

This equation is true, which means the spring constant cancels out.

Now, let's find the volume of the copper sphere. The extension of the spring is directly proportional to the force applied, which is directly proportional to the weight of the copper sphere. The weight of an object is given by the equation:

Weight = mass * gravity

Since the force applied is 1N, we can equate it to the weight of the copper sphere:

1N = mass * gravity

The volume of a sphere can be calculated using the formula:

Volume = (4/3) * π * r^3

To find the radius of the sphere, we need to know the mass of the copper sphere. Unfortunately, the mass is not provided in the given information, so we cannot calculate the volume of the sphere without this information.

Therefore, without the mass of the copper sphere, we cannot determine the volume of the sphere.