Question

Помогите пожалуйста срочно отдам все баллы 1)почему внутри заряженного шара электрическое поле равно нулю ?2)как вычисляется электрическое поле на поверхности заряженного шара и за его пределами ?3)почему диэлектрические вещества понижают напряжённость электрического поля ?​

Answer 1

а)Из-за того, что напряженность поля, созданного в точке за пределами заряженного шара, одинаковы с полем, созданным точечным зарядом, напряженность поля, созданного в точке за пределами шара, определяется по формуле:

б).

Напряженность электрического поля зависит от свойств среды, в которой расположен заряд, создающий поле. Рассмотрим случай, когда между двумя противоположно заряженными пластинами помещен диэлектрик

Объяснение:

Answer 2

Why is the electric field inside a charged sphere zero?

Inside a charged sphere, the electric field is zero because of the principle of electrostatic equilibrium. In an electrostatically balanced system, the charges distribute themselves in such a way that the electric field cancels out inside the conductor. This means that the charges redistribute themselves until the electric field inside the conductor becomes zero.

According to Gauss's law, the electric field inside a conductor is zero when it is in electrostatic equilibrium. This is because any electric field inside the conductor would cause the free charges to move, resulting in a redistribution of charges until the electric field becomes zero. Therefore, inside a charged sphere, the electric field is zero [[1]].

How is the electric field calculated on the surface of a charged sphere and outside it?

To calculate the electric field on the surface of a charged sphere, we can use Coulomb's law. Coulomb's law states that the electric field at a point due to a charged object is directly proportional to the charge and inversely proportional to the square of the distance from the charge.

On the surface of a charged sphere, the electric field can be calculated by considering the charge distribution of the sphere as if it were concentrated at its center. The electric field at any point on the surface of the sphere is given by the equation:

E = k * Q / r^2

Where: - E is the electric field - k is the electrostatic constant (approximately 9 x 10^9 Nm^2/C^2) - Q is the total charge of the sphere - r is the radius of the sphere

Outside the charged sphere, the electric field can be calculated using the same equation. However, the distance r is measured from the center of the sphere to the point where the electric field is being calculated.

Why do dielectric materials reduce the intensity of an electric field?

Dielectric materials, also known as insulators, reduce the intensity of an electric field due to their ability to polarize in the presence of an electric field. When a dielectric material is placed in an electric field, the electric field causes the charges within the dielectric material to separate, creating positive and negative charges on opposite sides of the material.

This separation of charges creates an internal electric field within the dielectric material that opposes the external electric field. As a result, the overall electric field within the dielectric material is reduced compared to the external electric field.

The reduction in the intensity of the electric field within the dielectric material is quantified by the relative permittivity (εr) of the material. The relative permittivity is a measure of how much the electric field is reduced within the dielectric material compared to a vacuum. It is defined as the ratio of the electric field in a vacuum to the electric field in the dielectric material.

Dielectric materials are commonly used in capacitors to increase their capacitance by reducing the electric field between the capacitor plates. This allows for the storage of more charge at a given voltage.

I hope this helps! Let me know if you have any further questions.