Question

Даю 150 баллов!! Физика 7 класс!!! Сила 20Н розтягує пружину на 4 см. Яка жорсткість пружини?​

Answer 1

Ответ:

По закону Гука F=k*x

k=F/x=20/0,04=500 H/

Answer 2

Calculating the Stiffness of the Spring

To calculate the stiffness of the spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = kx

Where: - F is the force applied to the spring (20N in this case) - k is the stiffness of the spring (what we want to find) - x is the displacement of the spring from its equilibrium position (4 cm or 0.04 m)

We can rearrange the formula to solve for the stiffness k:

k = F / x

Calculating the Stiffness

Using the given values: - F = 20N - x = 0.04m

We can calculate the stiffness of the spring using the formula:

k = 20N / 0.04m = 500 N/m

So, the stiffness of the spring is 500 N/m.