Question

Чему равна архимедова сила, действующая на тело объёмом 8 м3, наполовину погружённое в воду? Плотность воды 1000 кг/м3. * ​

Answer 1

Ответ: 40кН

Объяснение:

Дано:

V=8м³

ρ=1000кг/м³

-------------------

Fa-?

Fa=ρgV/2=1000*10*8/2=40000Н=40кН

Answer 2

Archimedes' Principle and Buoyant Force

Archimedes' principle states that when an object is partially or fully submerged in a fluid, it experiences an upward buoyant force equal to the weight of the fluid displaced by the object. This buoyant force can be calculated using the formula:

Buoyant force = density of the fluid × volume of the fluid displaced × acceleration due to gravity.

In this case, we have a body with a volume of 8 m^3, half of which is submerged in water. The density of water is given as 1000 kg/m^3.

To find the buoyant force acting on the body, we need to calculate the volume of water displaced by the submerged portion of the body. Since half of the body is submerged, the volume of water displaced is half of the total volume of the body, which is 4 m^3.

Now we can calculate the buoyant force using the formula mentioned earlier:

Buoyant force = density of water × volume of water displaced × acceleration due to gravity.

Substituting the given values:

Buoyant force = 1000 kg/m^3 × 4 m^3 × 9.8 m/s^2.

Calculating this, we find that the buoyant force acting on the body is 39,200 N.

Please note that the accuracy of this calculation depends on the accuracy of the given values and assumptions made.