Question

4. Тело объёмом 450 см3 погружено в машинное масло плотностью 800 кг/м3. архимедову силу, действующую на это тело​

Answer 1

Ответ: 3,6 Н

Объяснение:

F арх=ρ*V*g=800кг/м³* 0, 00045м³*9,8 Н/кг=3,6 Н

Answer 2

Calculating the Buoyant Force

To calculate the buoyant force acting on the object submerged in the oil, we can use the formula:

Buoyant force (F) = *density of the fluid (ρ) × volume of the fluid displaced (V) × acceleration due to gravity (g)*

Given: - Volume of the object (V) = 450 cm^3 - Density of the oil (ρ) = 800 kg/m^3

First, we need to convert the volume of the object from cm^3 to m^3: - 1 cm^3 = 1 × 10^-6 m^3

So, the volume of the object in m^3 is: - V = 450 cm^3 × (1 × 10^-6 m^3/cm^3) = 0.00045 m^3

Now, we can calculate the buoyant force using the given density of the oil and the volume of the object: - F = ρ × V × g - F = 800 kg/m^3 × 0.00045 m^3 × 9.8 m/s^2

Let's calculate the buoyant force using the given values.

Calculation

Using the given values: - F = 800 kg/m^3 × 0.00045 m^3 × 9.8 m/s^2 - F ≈ 3.96 N

So, the buoyant force acting on the object submerged in the oil is approximately 3.96 N.

[[SOURCE #4]]