Question

СРОЧНОО!! оптична сила розсіювальної лінзи -4дптр. предмет розташований на відстані 1 м лінзи. визначте відстань від лінзи до уявного зображення предмета

Answer 1

Ответ:

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Answer 2

Optics Problem: Calculating the Distance to the Virtual Image

To calculate the distance from the lens to the virtual image of the object, we can use the lens formula:

1. Lens Formula: The lens formula is given by: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] Where: - \( f \) = focal length of the lens - \( v \) = image distance - \( u \) = object distance

Given: - Focal length (\( f \)) = -4 diopters (since the lens is a diverging lens, the focal length is negative) - Object distance (\( u \)) = 1 m

We need to find the image distance (\( v \)).

Calculating the Image Distance:

Using the lens formula, we can rearrange it to solve for \( v \): \[ \frac{1}{v} = \frac{1}{f} + \frac{1}{u} \]

Substitute the given values: \[ \frac{1}{v} = \frac{1}{-4} + \frac{1}{1} \] \[ \frac{1}{v} = -\frac{1}{4} + 1 \] \[ \frac{1}{v} = \frac{3}{4} \] \[ v = \frac{4}{3} \]

So, the image distance (\( v \)) is \( \frac{4}{3} \) meters.

Conclusion:

The distance from the lens to the virtual image of the object is \( \frac{4}{3} \) meters.