Question

СРОЧНО 50 БАЛОВ Обчисліть енергію спокою пляшки мінеральної води масою 2 кг. Швидкість поширення світла у вакуумі 3*108 м/с.

Answer 1

Ответ:

18×10¹⁶ Дж

Объяснение:

Е=mc²=2×3×10⁸×3×10⁸=18×10¹⁶ Дж

Answer 2

Calculating Rest Energy of a Mineral Water Bottle

To calculate the rest energy of a mineral water bottle, we can use Einstein's famous equation, E=mc^2, where E represents energy, m represents mass, and c represents the speed of light in a vacuum.

Given: - Mass (m) = 2 kg - Speed of light in a vacuum (c) = 3*10^8 m/s

Calculation

Using the formula E=mc^2, we can calculate the rest energy of the mineral water bottle.

E = mc^2 E = 2 kg * (3*10^8 m/s)^2

Result

Calculating the result gives us the rest energy of the mineral water bottle.

E = 2 kg * (3*10^8 m/s)^2 = 1.8*10^17 joules

So, the rest energy of a mineral water bottle with a mass of 2 kg is approximately 1.8*10^17 joules.