Question

С какой силой действует магнитное поле с индукцией 10мТл на проводник в котором сила тока 50А если длина активной части проводника 0,1м? Линии индукции поля и ток взаимно перпендикулярны?

Answer 1

Ответ:

50 мН

Объяснение:

B=0.01 Тл     I=50 A     L=0.1 м     B⊥I    F=?

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F=I*B*L=50*0.01*0.1=0.05 H

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Answer 2

Calculating the Force Exerted by a Magnetic Field on a Conductor

To calculate the force exerted by a magnetic field on a conductor, we can use the formula:

F = BIL

Where: - F is the force in Newtons - B is the magnetic field induction in Tesla (T) - I is the current in Amperes (A) - L is the length of the conductor in meters (m)

Given: - B = 10 mT = 10 × 10^-3 T - I = 50 A - L = 0.1 m

We can calculate the force using the given values:

F = (10 × 10^-3 T) × 50 A × 0.1 m

F = 0.05 N

So, the force exerted by the magnetic field with an induction of 10 mT on a conductor with a current of 50 A and a length of 0.1 m is 0.05 N.

Orientation of Magnetic Field Lines and Current

The orientation of the magnetic field lines and the current in the conductor is crucial in determining the direction of the force exerted on the conductor. However, the provided search results do not contain specific information related to the orientation of the magnetic field lines and the current in this scenario.

If you have any further questions or need additional information, feel free to ask!