Question

На пружине жёсткостью 720 Н/м совершает колебание груз массой 200г с амплитудой 10 см. Чему равна наибольшая скорость движения груза? В каком положении она достигается? Ответ должен быть 6 м/с, НО ПОЖАЛУЙСТА РЕШИТЕ

Answer 1

Ответ:

рнрвовлсосо вьаьалалал

Answer 2

Calculation of Maximum Velocity

To calculate the maximum velocity of the mass on the spring, we can use the equation for simple harmonic motion:

v_max = Aω

where: - v_max is the maximum velocity - A is the amplitude of the oscillation (10 cm or 0.1 m in this case) - ω is the angular frequency

The angular frequency can be calculated using the formula:

ω = √(k/m)

where: - k is the spring constant (720 N/m in this case) - m is the mass of the object (200 g or 0.2 kg in this case)

Let's calculate the maximum velocity using these formulas:

ω = √(720/0.2) = √3600 = 60 rad/s

v_max = 0.1 * 60 = 6 m/s

Therefore, the maximum velocity of the mass on the spring is 6 m/s.

Position of Maximum Velocity

The maximum velocity is reached when the mass is at the equilibrium position (the center of its oscillation). In simple harmonic motion, the velocity is maximum at the equilibrium position and decreases as the mass moves away from it.

Therefore, the maximum velocity of 6 m/s is reached when the mass is at the center of its oscillation.

I hope this helps! Let me know if you have any further questions.