Question

2. Тело объемом 0,2м³ плавает в воде. Определите силу Архимеда,если плотность воды равна 1000кг/м³ (g=10H/кг) . ПОМОГИТЕ ПОЖАЛУЙСТА​

Answer 1

Ответ:

2 кН

Объяснение:

$F_{A}$ = ρgV

$F_{A}$ = 1000 * 10 * 0,2 = 2000 Н = 2 кН

Answer 2

Calculating the Force of Archimedes

To calculate the force of Archimedes, we can use the formula:

Archimedes' force = weight of the fluid displaced by the body

The weight of the fluid displaced by the body can be calculated using the formula:

Weight = volume × density × acceleration due to gravity

Given: - Volume of the body (V) = 0.2 m³ - Density of water (ρ) = 1000 kg/m³ - Acceleration due to gravity (g) = 10 m/s²

Let's calculate the force of Archimedes using the provided values.

Calculation

The weight of the fluid displaced by the body can be calculated as follows:

Weight = V × ρ × g

Substituting the given values: Weight = 0.2 m³ × 1000 kg/m³ × 10 m/s²

Weight = 2000 N

So, the force of Archimedes acting on the body is 2000 Newtons.

Therefore, the force of Archimedes acting on the body is 2000 Newtons.