Question

Яку силу потрібно прикласти до тіла масою 10 кг, щоб втримати його у воді, якщо його об'єм 0,004 м³​

Answer 1

Ответ: 60Н

Объяснение:

Дано:

m=10кг

V=0,004м³

ρ=1000кг/м³

g=10Н/кг

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F-?

F=Р-Fa=mg-ρgV=g(m-ρV)=10*(10-1000*0,004)=60Н

Answer 2

Calculating the Force Required to Hold a 10 kg Object in Water

To calculate the force required to hold a 10 kg object in water, we can use the principle of buoyancy and Archimedes' principle.

Step 1: Calculate the Buoyant Force According to Archimedes' principle, the buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. The formula for the buoyant force is:

Buoyant force = Weight of the fluid displaced

The weight of the fluid displaced can be calculated using the formula: Weight = density × volume × acceleration due to gravity

Given: - Mass of the object (m) = 10 kg - Volume of the object (V) = 0.004 m³ - Density of water (ρ) = 1000 kg/m³ (density of water)

Step 2: Calculate the Weight of the Fluid Displaced Using the formula: Weight = density × volume × acceleration due to gravity

Substitute the given values: Weight = 1000 kg/m³ × 0.004 m³ × 9.81 m/s²

Step 3: Calculate the Buoyant Force The buoyant force is equal to the weight of the fluid displaced, so: Buoyant force = 1000 kg/m³ × 0.004 m³ × 9.81 m/s²

Now, let's calculate the buoyant force using the given values.

The buoyant force can be calculated as follows: Buoyant force = 1000 kg/m³ × 0.004 m³ × 9.81 m/s² = 39.24 N

Conclusion

To hold a 10 kg object in water with a volume of 0.004 m³, a force of approximately 39.24 Newtons would need to be applied to counteract the buoyant force and keep the object from floating.