Question

Определите плотность жидкости, если Гидростатическое давление составляет 10000 Па, а Высота столба жидкости составляет 1 м. (ответ Г записать в см3 |​

Answer 1

Ответ:

$\rho =$ 1 г/см³

Объяснение:

Дано:

$p =$ 10 000 Па

$h =$ 1 м

$g =$ 10 м/c²

Найти:

$\rho \ - \ ?$

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Решение:

$p = \rho g h \Longrightarrow \boxed{ \rho = \dfrac{p}{gh} }$

$\rho =$ (10 000 Па) / (10 м/c² * 1 м) = 1000 кг/м³ = 1 г/см³

Ответ: $\rho =$ 1 г/см³.

Answer 2

Calculating the Density of a Liquid

To calculate the density of a liquid when the hydrostatic pressure is 10000 Pa and the height of the liquid column is 1 m, we can use the formula for hydrostatic pressure and the concept of density.

The formula for hydrostatic pressure is given by:

P = ρgh

Where: - P = hydrostatic pressure - ρ = density of the liquid - g = acceleration due to gravity - h = height of the liquid column

We can rearrange this formula to solve for density (ρ):

ρ = P / (gh)

Substituting the given values: - P = 10000 Pa - g = 9.81 m/s^2 (standard acceleration due to gravity) - h = 1 m

We can now calculate the density of the liquid using the given values.

Calculation

Using the formula ρ = P / (gh): - ρ = 10000 / (9.81 * 1) - ρ ≈ 1019.42 kg/m^3

To convert the density from kg/m^3 to cm^3/g, we can use the fact that 1 kg/m^3 is equal to 0.001 g/cm^3.

Converting the density: - ρ ≈ 1019.42 kg/m^3 - ρ ≈ 1.01942 g/cm^3

Therefore, the density of the liquid is approximately 1.01942 g/cm^3.

Conclusion

The density of the liquid, given the hydrostatic pressure of 10000 Pa and a liquid column height of 1 m, is approximately 1.01942 g/cm^3.