Question

Тело объемом 120 см^3 погружено в воду, определите архимедову силу, действующую на тело.​

Answer 1

Ответ:

Дано:

V=120cм^3=120×10^-6м^3

р(в)=1000кг/м^3

Fa=p(ж)gV(т)=1000кг/м^3×10Н/м×120×10^-6м^3=1,2Н

Fa=1,2Н

Answer 2

Ответ:

Fa = p (жидкости) × g × V т. = 1000 кг/м³ × 9,8 Н/кг × 0,00012 м³ = 1,176 Н

Answer 3

Archimedes' Principle and Buoyant Force

To determine the Archimedes' force acting on an object submerged in water, we need to consider Archimedes' principle. According to Archimedes' principle, an object submerged in a fluid experiences an upward force called the buoyant force, which is equal to the weight of the fluid displaced by the object.

The formula to calculate the buoyant force is:

F = ρ * V * g

Where: - F is the buoyant force - ρ is the density of the fluid (in this case, water) - V is the volume of the fluid displaced by the object - g is the acceleration due to gravity

In this case, the object has a volume of 120 cm^3 and is submerged in water. We can assume the density of water to be approximately 1000 kg/m^3.

Calculation of Buoyant Force

To calculate the buoyant force, we need to convert the volume of the object to cubic meters and substitute the values into the formula.

Given: - Volume of the object (V) = 120 cm^3 = 0.00012 m^3 - Density of water (ρ) = 1000 kg/m^3 - Acceleration due to gravity (g) = 9.8 m/s^2

Substituting the values into the formula:

F = 1000 kg/m^3 * 0.00012 m^3 * 9.8 m/s^2

Calculating the result:

F ≈ 0.1176 N

Therefore, the Archimedes' force acting on the object submerged in water is approximately 0.1176 Newtons.

Please note that the density of water and the acceleration due to gravity are approximate values commonly used for calculations.