Question

За напруги 220 В сила струму в резисторі дорівнює 5 А. Якою буде сила струму в цьому резисторі, якщо напругу зменшити до 88 В?

Answer 1

Дано:

U1=220 В

I=5 А

U2=88 В

I2-?

Розв'язання:

R=U1/I1=220/5=44 Ом

R=U2/I2 => I2=U2/R=88/44=2 А

Відповідь:I=2 А.

Answer 2

Calculation of Current in a Resistor

To calculate the current in a resistor when the voltage is reduced from 220V to 88V, we can use Ohm's Law. Ohm's Law states that the current flowing through a resistor is equal to the voltage across the resistor divided by the resistance of the resistor.

The formula for Ohm's Law is:

I = V / R

Where: - I is the current in Amperes (A) - V is the voltage in Volts (V) - R is the resistance in Ohms (Ω)

In this case, we know that the voltage is reduced from 220V to 88V, and the current in the resistor is initially 5A. We need to find the new current when the voltage is reduced.

Let's assume the resistance of the resistor remains constant.

Using Ohm's Law, we can rearrange the formula to solve for the resistance:

R = V / I

Substituting the given values:

Initial voltage (V1) = 220V Initial current (I1) = 5A

Resistance (R) = V1 / I1 = 220V / 5A = 44Ω

Now, we can calculate the new current (I2) when the voltage is reduced to 88V:

New voltage (V2) = 88V

I2 = V2 / R

Substituting the values:

I2 = 88V / 44Ω = 2A

Therefore, when the voltage is reduced to 88V, the current in the resistor will be 2A.