Question

Задачи во Физике- 1. Тело выталкивается керосином с силой 80Н. определите объём тела. 2. С какой силой выталкивается из речной воды кусок железа объёмом 300 см3? 3.Деревянная пробка объёмом 15 см3 опущена в бензин. Определите с какой силой она выталкивается бензином.Срочно помогите- ДАЮ 30 БАЛЛОВ!!!! СРОЧНООООООООООООООООООООООООООООООООООООООООООООООООО

Answer 1

Ответ:

1)

Fa = p ж. × g × V т. => V = Fa/p×g

V = 80 H/800 кг/м³ × 9,8 Н/кг ≈ 0,01 м³

Ответ: V ≈ 0,01 м³

2)

1) 300 см³ = 0,0003 м³

2) Найдём вытакливающую силу по формуле:

Fa = p ж. × g × V т. = 1000 кг/м³ × 9,8 Н/кг × 0,0003 м³ = 2,94 Н

Ответ: Fa = 2,94 H

3)

1) 15 см³ = 0,000015 м³

2) Найдём вытакливающую силу по формуле:

Fa = p ж. × g × V т. = 710 кг/м³ × 9,8 Н/кг × 0,000015 м³ = 0,10437 Н ≈ 0,1 Н

Ответ: Fa ≈ 0,1 H

Answer 2

Task 1: Finding the volume of an object pushed by kerosene with a force of 80 N

To find the volume of an object pushed by kerosene with a force of 80 N, we need to use the concept of pressure. Pressure is defined as the force applied per unit area. The formula for pressure is:

Pressure = Force / Area

In this case, the force applied is 80 N. However, we don't have the area of the object, so we need more information to solve this problem. Could you please provide the area of the object?

Task 2: Finding the force required to push an iron piece with a volume of 300 cm³ out of river water

To find the force required to push an iron piece with a volume of 300 cm³ out of river water, we need to use the concept of buoyancy. Buoyancy is the upward force exerted on an object submerged in a fluid.

The formula to calculate the buoyant force is:

Buoyant Force = Weight of the Fluid Displaced

To find the weight of the fluid displaced, we need to know the density of the fluid. Could you please provide the density of the river water?

Task 3: Finding the force required to push a wooden cork with a volume of 15 cm³ out of gasoline

To find the force required to push a wooden cork with a volume of 15 cm³ out of gasoline, we can again use the concept of buoyancy. The buoyant force exerted on the cork is equal to the weight of the fluid displaced.

The formula to calculate the buoyant force is the same as mentioned in Task 2:

Buoyant Force = Weight of the Fluid Displaced

To find the weight of the fluid displaced, we need to know the density of the gasoline. Could you please provide the density of the gasoline?

Please provide the missing information for both Task 1 and Task 3 so that we can help you further.