
Яка сила тяжіння діє на мідну кулю об'ємом 300 см кубічних


Ответы на вопрос

Ответ: 26,7Н
Объяснение:
Дано:
V=300cм³
ρ=8,9г/см³
g=10Н/кг
-----------------
Fт-?
Fт=mg=ρVg/1000=8,9*300*10/1000=26,7Н



Gravitational Force on a Copper Sphere
The gravitational force acting on a copper sphere with a volume of 300 cubic centimeters can be calculated using the formula for gravitational force:
F = (G * m1 * m2) / r^2
Where: - F is the gravitational force - G is the gravitational constant (approximately 6.674 × 10^-11 N m^2/kg^2) - m1 and m2 are the masses of the two objects (in this case, the copper sphere and the Earth) - r is the distance between the centers of the two objects
To calculate the gravitational force on the copper sphere, we need to know the mass of the sphere and the distance between the center of the sphere and the center of the Earth.
The mass of the copper sphere can be calculated using its density and volume. The density of copper is approximately 8.96 grams per cubic centimeter.
m = density * volume
m = 8.96 g/cm^3 * 300 cm^3
m ≈ 2688 grams
Now, we need to convert the mass from grams to kilograms:
m ≈ 2.688 kilograms
The distance between the center of the Earth and the center of the copper sphere is approximately the radius of the Earth, which is about 6,371 kilometers (or 6,371,000 meters).
Now, we can calculate the gravitational force using the formula mentioned earlier.
F = (6.674 × 10^-11 N m^2/kg^2 * (mass of Earth) * (mass of copper sphere)) / (radius of Earth)^2
This calculation will give us the gravitational force acting on the copper sphere.
Let's calculate the gravitational force.


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