
В сообщающийся сосуд налита вода. Под действием силы F1 = 0,2 кн уровень воды опустился на
расстояние 16 см в левом сосуде, определите = какая сила была приложена в правой части и на какую высоту поднялась вода, если известно что площадь правого сосуда в 4 раза больше левого.

Ответы на вопрос

Ответ: 0,8кН; 4см
Объяснение:
Дано:
F=0,2кН=200Н
h1=16cм
S1=S
S2=4S
-------------
F2-?; h1-?
F1*S1=F2*S
F1*S=F2*4S
F2=F1*4S/S=4F1=4*0,2=0,8кН
V1=V2
h1*S=h2*4S
h2=h1/4=16/4=4cм
h2=



Calculation of the Force and Height of Water
To determine the force applied in the right part of the vessel and the height to which the water rose, we can use the principle of Pascal's law, which states that when pressure is applied to a fluid in a closed container, it is transmitted equally in all directions.
Given that the force applied in the left part of the vessel (F1) is 0.2 kN and the water level in the left vessel has dropped by 16 cm, we can calculate the force applied in the right part of the vessel and the height to which the water rose.
Let's assume that the area of the left vessel is A, and the area of the right vessel is 4A (as stated in the question).
According to Pascal's law, the pressure exerted by the water in the left vessel is equal to the pressure exerted by the water in the right vessel.
The pressure exerted by the water in the left vessel can be calculated using the formula:
Pressure = Force / Area
The pressure exerted by the water in the right vessel can be calculated using the same formula:
Pressure = Force / Area
Since the area of the right vessel is 4 times larger than the area of the left vessel, the force applied in the right part of the vessel can be calculated as:
Force in the right part = Force in the left part * (Area of the right vessel / Area of the left vessel)
Now, let's calculate the force applied in the right part of the vessel:
Force in the right part = 0.2 kN * (4A / A) = 0.8 kN
Therefore, the force applied in the right part of the vessel is 0.8 kN.
To calculate the height to which the water rose in the right vessel, we can use the equation:
Pressure = Density * Gravity * Height
Since the pressure exerted by the water in both vessels is the same, we can equate the two equations:
Force in the left part / Area of the left vessel = Force in the right part / Area of the right vessel
Substituting the values we have:
0.2 kN / A = 0.8 kN / (4A)
Simplifying the equation:
0.2 / A = 0.8 / (4A)
Cross-multiplying:
0.2 * (4A) = 0.8 * A
Simplifying further:
0.8A = 0.8A
This equation shows that the value of A cancels out, meaning the value of A is not needed to determine the height to which


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