Question

Трактор тягне плуг зі сталою швидкістю 5.4 км/год, прикладаючи до НЬOГO силу 50 кН. Яку потужність розвиває двигун трактора?​

Answer 1

Дано:

υ=5,4 км/год=1,5 м/с

F=50 кН=50000 H

P-?

Розв'язання:

P=A/t; A=Fs => P=Fs/t; υ=s/t => P=Fυ

P=50000 H*1,5 м/с=75000 Вт=75 кВт

Відповідь:P=75000 Вт.

P.s.Якщо у вас потужність позначається буквою N,то замість P пишіть N.

Answer 2

Ответ:

7 кВт

Объяснение:

N = F V = 5 000 * 1,5 =7 500 Вт = 7 кВт

5,4 км/час = 1,5 м/с

Answer 3

Calculating Tractor Engine Power

To calculate the power developed by the tractor's engine, we can use the formula:

Power (P) = Force (F) × Velocity (V)

Where: - Force (F) is the force applied by the tractor, measured in kilonewtons (kN). - Velocity (V) is the velocity at which the force is applied, measured in kilometers per hour (km/h).

Given: - Force (F) = 50 kN - Velocity (V) = 5.4 km/h

Calculating Power

Using the given values, we can calculate the power developed by the tractor's engine:

Power (P) = Force (F) × Velocity (V) Power (P) = 50 kN × 5.4 km/h

Now, let's convert the velocity from kilometers per hour to meters per second, as power is typically measured in watts, which is a unit of energy per unit time in the International System of Units (SI).

1 km/h = 0.277778 m/s

So, the velocity in meters per second is: 5.4 km/h × 0.277778 m/s = 1.499992 m/s

Now, we can calculate the power: Power (P) = 50 kN × 1.499992 m/s

Result

The power developed by the tractor's engine can be calculated as follows: Power (P) = 50 kN × 1.499992 m/s = 74.9996 kilowatts (kW)

Therefore, the engine of the tractor develops approximately 74.9996 kilowatts (kW) of power when pulling the plow at a speed of 5.4 km/h with a force of 50 kN.