Question

СРОЧНО МОЛЮНа якій глибині тиск в морі становить418кПа​

Answer 1

Ответ: h=40(m)

Объяснение:

Дано:

ρ=$1030\frac{kg}{m^{3} }$

p=418kПа=418000Па

h - ?

1) p=ρgh ⇒ h=$\frac{p}{1030\frac{kg}{m^{3} }g }$=$\frac{418000}{10300}$≈40(m)

Answer 2

Ответ:

40 м. Взято из учебника (задачника)

Answer 3

Water Pressure at 418 kPa

The pressure at a certain depth in the ocean can be calculated using the formula:

P = ρgh

Where: - P = pressure - ρ = density of the fluid - g = acceleration due to gravity - h = depth

Given that the pressure is 418 kPa, we can calculate the depth using this formula. The density of seawater is approximately 1025 kg/m³, and the acceleration due to gravity is approximately 9.81 m/s².

Using these values, we can rearrange the formula to solve for depth:

h = P / (ρg)

Substituting the given values: h = 418,000 Pa / (1025 kg/m³ * 9.81 m/s²)

Calculating this gives us the depth at which the pressure is 418 kPa.

Let's calculate this.