Question

v=12л T=27 градусов C P=2,2*10^5 Па M(O2)=32*10^-3 кг/моль m-?

Answer 1

Ответ:

≈34 г

Объяснение:

T=300 K    V=12*10⁻³ м³    p=2.2*10⁵ Па   M=32*10⁻³ кг/моль  m=?

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p*V=(m/M)R*T

m=p*V*M/(R*T)=2.2*10⁵*12*10⁻³*32*10⁻³/(8.31*300)≈0.034 кг

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Answer 2

To find the value of 'm,' we need to use the ideal gas law equation, which is given by:

PV = nRT

Where: P is the pressure in Pascals (Pa) V is the volume in cubic meters (m^3) n is the number of moles R is the ideal gas constant (8.314 J/(mol·K)) T is the temperature in Kelvin (K)

First, let's convert the given values to the correct units:

V = 12 L = 12 × 10^(-3) m^3 (since 1 L = 10^(-3) m^3) T = 27 degrees Celsius = 27 + 273.15 K (since the temperature needs to be in Kelvin)

Now, we can rearrange the ideal gas law equation to solve for 'n' (number of moles):

n = PV / RT

Given: P = 2.2 × 10^5 Pa V = 12 × 10^(-3) m^3 T = 27 + 273.15 K

Substituting these values into the equation, we get:

n = (2.2 × 10^5 Pa) × (12 × 10^(-3) m^3) / [(8.314 J/(mol·K)) × (27 + 273.15 K)]

Simplifying:

n = (2.2 × 12 × 10^5) / (8.314 × 300.15)

Now, we can calculate the value of 'n':

n ≈ 1.0 mol

Given that the molar mass of O2 (M(O2)) is 32 × 10^(-3) kg/mol, we can calculate the mass (m) using the following equation:

m = n × M(O2)

Substituting the values:

m = 1.0 mol × (32 × 10^(-3) kg/mol)

Simplifying:

m = 0.032 kg/mol

Therefore, the value of 'm' is approximately 0.032 kg/mol.