Question

E1=5*10^4 Н/Клr1=20 смr2=1 м E2=? ​

Answer 1

E2/E1=r1²/r2²

E2=2*10^-5 Н/Кл

Answer 2

To find E2, we can use the formula for electric field strength:

E = kQ/r^2

where E is the electric field strength, k is Coulomb's constant (k = 9 x 10^9 N m^2/C^2), Q is the charge that creates the electric field, and r is the distance from the charge to the point where the field is measured.

Since the problem gives us the electric field strength and distance for one charge (E1 and r1), we can solve for the charge Q using the formula:

Q = Er^2/k

Substituting the values given in the problem, we get:

Q = (5 x 10^4 N/C) x (0.2 m)^2 / (9 x 10^9 N m^2/C^2) ≈ 0.0022 C

Now we can use this charge to calculate the electric field strength at the second distance (E2):

E2 = kQ/r2^2

Substituting the values, we get:

E2 = (9 x 10^9 N m^2/C^2) x (0.0022 C) / (1 m)^2 ≈ 1.98 x 10^4 N/C

Therefore, the electric field strength at a distance of 1 meter from the charge is approximately 1.98 x 10^4 N/C.