Question

7b(2b+3)-(b+6)(b-3) когда b=-0.1​

Answer 1

Пошаговое объяснение:

7b(2b+3)-(b+6)(b-3) = 14b²+21b-b²+3b-6b+18 = 13b²+18b+18

13b²+18b+18 = 13*(-0.1)²+18*(-0.1)+18=0.13-1.8+18 = 16.33

Answer 2

To find the value of the expression 7b(2b+3)-(b+6)(b-3) when b = -0.1, we can substitute the value of b into the expression and simplify.

Let's start by substituting b = -0.1 into each term of the expression:

7b(2b+3) = 7*(-0.1)*(2*(-0.1)+3) = 7*(-0.2+3) = 7*2.8 = 19.6

(b+6)(b-3) = (-0.1+6)*(-0.1-3) = 5.9*(-3.1) = -18.29

Now, let's substitute these values back into the original expression:

7b(2b+3)-(b+6)(b-3) = 19.6 - (-18.29) = 19.6 + 18.29 = 37.89

Therefore, when b = -0.1, the value of the expression 7b(2b+3)-(b+6)(b-3) is 37.89.