Question

Помогите решить задачу. Школьная эскурсия в соседний город продолжалась двое суток и 5 часов. Ученики вернулись с экскурсии 20 июля в 12часов дня. Определи в какой день месяц и час дети уехали на экскурсию.

Answer 1

20-2=18 
12-5=7
Дети уехали 18 июля в 7 часов утра.

Answer 2

Problem Analysis

To determine the day, month, and time the students left for the excursion, we need to subtract the duration of the excursion from the return date and time.

Solution

1. Convert the duration of the excursion to hours: 2 days and 5 hours = (2 * 24) + 5 = 53 hours. 2. Subtract 53 hours from the return date and time of 20th July at 12:00 PM. 3. Calculate the new date and time.

Calculation

- Return date and time: 20th July at 12:00 PM. - Duration of the excursion: 53 hours.

Subtracting 53 hours from 20th July at 12:00 PM, we get:

20th July at 12:00 PM - 53 hours = 18th July at 11:00 AM.

Therefore, the students left for the excursion on 18th July at 11:00 AM.

Answer

The students left for the excursion on 18th July at 11:00 AM.

Please let me know if there is anything else I can help#### Problem Analysis To determine the day, month, and time the students left for the excursion, we need to subtract the duration of the excursion from the return date and time.

Solution

1. Convert the duration of the excursion to hours: 2 days and 5 hours = (2 * 24) + 5 = 53 hours. 2. Subtract 53 hours from the return date and time of 20th July at 12:00 PM. 3. Calculate the new date and time.

Calculation

- Return date and time: 20th July at 12:00 PM. - Duration of the excursion: 53 hours.

Subtracting 53 hours from 12:00 PM on 20th July, we get the departure time as 11:00 AM on 18th July.

Therefore, the students left for the excursion on 18th July at 11:00 AM.

Please let me know if you need any further assistance.