Question

В цилиндрический сосуд налили 1200 воды . уровень воды при этом достигает высоты 12 см. в жидкость полностью погрузили деталь. при этом жидкости в сосуде поднялся на 10 см. чему равен объем детали?! ответ выразить в см

Answer 1

Vцилиндра = Sоснования × h
1 мл=1см³
Sоснования =1200:12=100 (см²)
По закону Архимеда объем детали будет равен объёму "вытесненной" жидкости. Найдём объём жидкости.
V=S×h=100×10=1000 (см³)

Answer 2

Calculation of the Volume of the Object

To calculate the volume of the object submerged in the cylindrical vessel, we can use the principle of displacement. According to Archimedes' principle, the volume of the object is equal to the volume of liquid displaced by the object when it is submerged.

Given: - The vessel initially contains 1200 cm³ of water, and the water level reaches a height of 12 cm. - When the object is fully submerged, the water level rises by 10 cm.

To find the volume of the object, we need to calculate the difference in volume before and after the object is submerged.

1. Calculate the initial volume of water in the vessel: - Initial water level = 12 cm - Cross-sectional area of the vessel = A (cm²) - Initial volume of water = A * 12 cm³

2. Calculate the volume of water displaced by the object: - Water level rise = 10 cm - Volume of water displaced = A * 10 cm³

3. Calculate the volume of the object: - Volume of the object = Volume of water displaced

Note: To calculate the volume of the object, we need the cross-sectional area of the vessel. Unfortunately, the search results provided do not contain the necessary information to determine the cross-sectional area. Therefore, without the cross-sectional area, we cannot calculate the volume of the object accurately.

If you have any additional information or measurements regarding the vessel or object, please provide them so that we can assist you further.