Question

Из двух пунктов расстояние между которыми 63 км одновременно навстречу друг другу выехал мотоциклист и велосипедист и встретились через 1,2 часа найти скорость мотоциклиста если велосипидист ехал со скоростью на 27,5 км в час меньше скорости мотоциклиста помогите плиз

Answer 1

Ответ:х=40!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

Х - скорость мотоциклиста
х-27.5 скорость велосипедиста
скорость сближения х+х-27.5=2х-27.5
(2х-27.5)*1.2=63
х=40
Ответ 40 км в час скорость мотоциклиста

Answer 3

Problem Analysis

We are given that a motorcyclist and a cyclist start simultaneously from two points that are 63 km apart and travel towards each other. They meet after 1.2 hours. We are also given that the cyclist's speed is 27.5 km/h less than the motorcyclist's speed. We need to find the speed of the motorcyclist.

Solution

Let's assume the speed of the motorcyclist is x km/h. Since the cyclist's speed is 27.5 km/h less than the motorcyclist's speed, the cyclist's speed will be x - 27.5 km/h.

We can use the formula distance = speed × time to solve this problem. The total distance between the two points is 63 km, and they meet after 1.2 hours.

The motorcyclist travels a distance of x × 1.2 km, and the cyclist travels a distance of (x - 27.5) × 1.2 km. The sum of these distances should be equal to the total distance of 63 km.

Therefore, we can write the equation: x × 1.2 + (x - 27.5) × 1.2 = 63

Simplifying the equation: 1.2x + 1.2x - 33 = 63 2.4x = 96 x = 40

Therefore, the speed of the motorcyclist is 40 km/h.