Question

На складе интернет-магазина упаковали в коробки 179 елочных шариков. Каждая из коробок вмещает 20 шариков. 1. Сколько упаковочных коробок потребуется? 2. Сколько упаковочных коробок будут заполнены полностью? 3. Сколько шариков будет в той коробке, которая будет заполнена не полностью? Запиши решение задачи с помощью деления с остатком. Запиши ответы на все вопросы задачи. СПАСИБО.

Answer 1

1. потребуется 19коробок
2. 18 коробок будут заполнены полностью
3. 19 шариков
4. 179/20=8,95

Answer 2

1. To determine the number of packaging boxes required, we divide the total number of Christmas balls by the capacity of each box. In this case, there are 179 Christmas balls and each box can hold 20 balls.

Using division, we can calculate the number of packaging boxes needed as follows: 179 balls ÷ 20 balls per box = 8.95 boxes

Since we cannot have a fraction of a box, we need to round up to the nearest whole number. Therefore, we will need 9 packaging boxes in total.

2. To find out how many packaging boxes will be filled completely, we need to determine the number of boxes that can hold the exact number of balls without any remaining space.

Using division again, we can calculate the number of fully filled boxes as follows: 179 balls ÷ 20 balls per box = 8.95 boxes

Since we cannot have a fraction of a box, we need to round down to the nearest whole number. Therefore, 8 packaging boxes will be filled completely.

3. To determine the number of balls in the box that will not be filled completely, we need to find the remainder when dividing the total number of balls by the capacity of each box.

Using the modulo operator (%), we can calculate the number of balls in the partially filled box as follows: 179 balls % 20 balls per box = 19 balls

Therefore, the box that is not filled completely will contain 19 balls.

In summary: 1. The number of packaging boxes required is 9. 2. The number of packaging boxes that will be filled completely is 8. 3. The box that is not filled completely will contain 19 balls.

I hope this helps! Let me know if you have any further questions.