Question

Из резервуара с керосином отлили вначале 2/5, потом 1/3 всего керосина и после этого в резервуаре осталось 8 тонн керосина. Сколько керосина было в резервуаре первоночально

Answer 1

1)2/5+1/3=11/15 отлили всего
2)1-11/15=4/15-осталось
3)х-было изначально
4/15*х=8
х= 30 т было изначально

Answer 2

2/5+1/3=6/15+5/15=11/15 отлили
1-11/15=4/15 осталось,что составляет 8т
8:4/15=8*15/4=30т керосина было в резервуаре первоначально

Answer 3

Calculating the Initial Amount of Kerosene in the Tank

To calculate the initial amount of kerosene in the tank, we can use the information provided. The problem states that initially, 2/5 of the kerosene was poured out, then 1/3 of the remaining kerosene was poured out, leaving 8 tons of kerosene in the tank.

Let's denote the initial amount of kerosene as x tons.

1. Pouring out 2/5 of the kerosene: - After pouring out 2/5 of the kerosene, the amount left in the tank is: (3/5)x tons.

2. Pouring out 1/3 of the remaining kerosene: - After pouring out 1/3 of the remaining kerosene, the amount left in the tank is: (2/3)(3/5)x = (2/5)x tons.

3. Given amount of kerosene left: - The problem states that after these operations, 8 tons of kerosene are left in the tank.

We can set up the equation: \[(2/5)x = 8\]

Solving for x will give us the initial amount of kerosene in the tank.

Calculating the Initial Amount of Kerosene

Using the equation \[(2/5)x = 8\], we can solve for x:

\[(2/5)x = 8\]

\[x = 8 / (2/5)\]

\[x = 8 * (5/2)\]

\[x = 20\]

So, the initial amount of kerosene in the tank was 20 tons.

Therefore, the initial amount of kerosene in the tank was 20 tons.

Answer 4

Problem Analysis

We are given that 2/5 of the kerosene was poured out of a reservoir, then 1/3 of the remaining kerosene was poured out, leaving 8 tons of kerosene in the reservoir. We need to determine the initial amount of kerosene in the reservoir.

Solution

Let's assume the initial amount of kerosene in the reservoir is x tons.

According to the problem, 2/5 of the kerosene was poured out, leaving 3/5 of the initial amount in the reservoir: 3/5 * x = remaining amount after the first pouring

Then, 1/3 of the remaining kerosene was poured out, leaving 8 tons in the reservoir: (2/3) * (3/5 * x) = 8

To find the initial amount of kerosene, we can solve this equation for x.

Calculation

Let's solve the equation:

(2/3) * (3/5 * x) = 8

First, simplify the equation:

(2/3) * (3/5 * x) = 8 (2/3) * (3/5) * x = 8 (2/5) * x = 8

Now, isolate x:

(2/5) * x = 8 x = 8 * (5/2) x = 20

Answer

The initial amount of kerosene in the reservoir was 20 tons.