Question

Из 30 шариков, лежащих в коробке, 24 красных; во второй коробке из 50 шариков 25 красных; в третьей - из 100 шариков 40 красных. Из каждой коробки не глядя вынимают один шарик. В каком случае вероятнее всего вынуть красный шарик? ВНИМАНИЕ ЗАДАЧА НА ОТНОШЕНИЕ!!! ПОМОГИТЕ ПОЖАЛУЙСТА, БУДУ ОЧЕНЬ БЛАГОДАРНО!!!!!!!

Answer 1

24:30=0.8 в первой коробке

25:50=0.5 во второй коробке

40:100=0.4 в третьей коробке

0.8>0.5>0.4, соответственно,

24/30>25/50>40/100, значит вероятность вынуть красный шарик больше в первой коробке

Answer 2

В первой коробке равна 24/30=0,8.

Во второй коробке равна 25/50=0,5.

В третьей коробке равна 40/100=0,4.
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Удачи! 

Answer 3

Problem Analysis

In this problem, we have three boxes with different numbers of balls, and we want to determine which box has the highest probability of drawing a red ball. Let's analyze the information given:

- Box 1: 30 balls, 24 red balls - Box 2: 50 balls, 25 red balls - Box 3: 100 balls, 40 red balls

We need to calculate the probability of drawing a red ball from each box and compare them to determine which box has the highest probability.

Solution

To find the probability of drawing a red ball from each box, we divide the number of red balls in each box by the total number of balls in that box.

Let's calculate the probabilities for each box:

- Box 1: Probability of drawing a red ball = 24/30 = 0.8 - Box 2: Probability of drawing a red ball = 25/50 = 0.5 - Box 3: Probability of drawing a red ball = 40/100 = 0.4

From the calculations, we can see that the box with the highest probability of drawing a red ball is Box 1, with a probability of 0.8.

Conclusion

In this scenario, the box with the highest probability of drawing a red ball is Box 1, which has a probability of 0.8.