Question

Самолет был в полёте в первый день 5часов ,а второй 8часов и летели всё время с одинаковой скоростью в первый день самолет пролетел на 1620км меньше, чем второй. Сколько км самолёт пролетел в первый день ????

Answer 1

1620÷(8-5)×5=2700(км.)-пролетел самолёт в первый день ;

Answer 2

Calculation of the Distance Flown on the First Day

To calculate the distance flown on the first day, we can set up an equation based on the given information. Let's assume that the speed of the plane is represented by x km/h.

On the first day, the plane flew for 5 hours, so the distance flown on the first day can be calculated as 5x km.

On the second day, the plane flew for 8 hours, so the distance flown on the second day can be calculated as 8x km.

According to the given information, the distance flown on the first day is 1620 km less than the distance flown on the second day. Therefore, we can set up the following equation:

8x - 5x = 1620

Simplifying the equation, we get:

3x = 1620

Solving for x, we divide both sides of the equation by 3:

x = 540

So, the speed of the plane is 540 km/h.

To find the distance flown on the first day, we substitute the value of x into the equation 5x:

5 * 540 = 2700

Therefore, the plane flew 2700 km on the first day.

Please let me know if there is anything else I can help you with!