Question

От одной пристани одновременно в противоположных направлениях отплыли два катера.Средняя скорость одного на 10км/ч больше,чем другого.Через 2 ч расстояние между катерами равнялось 140 км. С какой скоростью двигался каждый катер?

Answer 1

140/2=70 - скорость удаления

70-10=60

60/2=30 - скорость одного катера

30+10=40км/час - скорость второго катера

или так:

(140/2=70 - скорость удаления

х- скорость первого катера

х+х+10=70

2х=60

х=30

30+10=40)

Answer 2

Problem Analysis

We have two boats that depart from the same dock simultaneously in opposite directions. The average speed of one boat is 10 km/h greater than the other. After 2 hours, the distance between the boats is 140 km. We need to find the speed of each boat.

Solution

Let's assume the speed of the slower boat is x km/h. Therefore, the speed of the faster boat will be x + 10 km/h.

We know that the distance traveled by each boat is equal to their respective speeds multiplied by the time. After 2 hours, the distance between the boats is 140 km. Therefore, we can set up the following equation:

2x + 2(x + 10) = 140

Simplifying the equation:

2x + 2x + 20 = 140

4x + 20 = 140

4x = 120

x = 30

The speed of the slower boat is 30 km/h, and the speed of the faster boat is 30 + 10 = 40 km/h.

Therefore, the slower boat was moving at a speed of 30 km/h, and the faster boat was moving at a speed of 40 km/h.

Answer

The slower boat was moving at a speed of 30 km/h, and the faster boat was moving at a speed of 40 km/h.