Question

Без ореха ( от дупла до орешника) белка бежит со скоростью 4 м/ сек, а с орехом ( от орешника до дупла) со скоростью 2 м/ сек. На путь от дупла до орешника и обратно она тратит 54 секунды ю. Найдите расстояние от дупла до орешника. Ответ обоснуйте?

Answer 1

Пусть без ореха ( от дупла до орешника) белка бежит х секунд со скоростью 4 м/ сек, а с орехом ( от орешника до дупла) (54-х) секунд со скоростью 2 м/ сек.
Путь без ореха равен пути с орехом, это расстояние от дупла до орешника
4х=2·(54-х)
4х=108-2х
4х+2х=108
6х=108
х=18
18·4=72 м - расстояние от дупла до орешника
Ответ. 72 м

Answer 2

Problem Analysis

We are given that a squirrel runs from point A to point B at a speed of 4 m/s and returns from point B to point A at a speed of 2 m/s. The total time taken for the round trip is 54 seconds. We need to find the distance between points A and B.

Solution

Let's assume the distance between points A and B is d.

The time taken to travel from A to B at a speed of 4 m/s is given by: time_AB = d / 4 The time taken to travel from B to A at a speed of 2 m/s is given by: time_BA = d / 2 The total time taken for the round trip is 54 seconds: time_AB + time_BA = 54

Substituting the values of time_AB and time_BA, we get: (d / 4) + (d / 2) = 54

Simplifying the equation: d/4 + 2d/4 = 54 3d/4 = 54 3d = 54 * 4 3d = 216 d = 216 / 3 d = 72

Therefore, the distance between points A and B is 72 meters.

Answer

The distance from point A to point B is 72 meters. This can be calculated by dividing the total time taken for the round trip (54 seconds) by the sum of the speeds of the squirrel (4 m/s + 2 m/s) and multiplying it by the speed of the squirrel while going from point A to point B (4 m/s).