Question

Помогите есть всего 5 минв 6 А классе учеников на 25% больше чем в шестом Б классе когда 3 учеников из 6 А класса перевели в шестой б то количество учеников в обоих классах стало ровным Сколько учеников ников было в каждом классе первоначально

Answer 1

3=25%
3(25%)×4=12(100%) их стало)
12%(100%)-3(25%)=9
12%(100%)+3(25%)=15
9учеников было в одном классе
15

Answer 2

Отвеееееееееет 12
стало 12

Answer 3

Problem Analysis

We are given that there are 5 minutes in class 6A, and the number of students in class 6A is 25% more than the number of students in class 6B. When 3 students from class 6A are transferred to class 6B, the number of students in both classes becomes equal. We need to determine the initial number of students in each class.

Solution

Let's assume the initial number of students in class 6B is x. Since the number of students in class 6A is 25% more than in class 6B, the number of students in class 6A can be expressed as x + 0.25x.

When 3 students from class 6A are transferred to class 6B, the number of students in class 6A becomes x + 0.25x - 3, and the number of students in class 6B becomes x + 3.

According to the problem, the number of students in both classes becomes equal after the transfer. Therefore, we can set up the following equation:

(x + 0.25x - 3) = (x + 3)

Simplifying the equation:

1.25x - 3 = x + 3

0.25x = 6

x = 6 / 0.25

x = 24

So, the initial number of students in class 6B is 24.

The initial number of students in class 6A can be calculated as x + 0.25x = 24 + 0.25(24) = 24 + 6 = 30.

Therefore, there were initially 24 students in class 6B and 30 students in class 6A.

Answer

The initial number of students in class 6B was 24, and the initial number of students in class 6A was 30.