Question

Помогите решить задачу номер 205. Два велосипедиста выехали одновременно навстречу друг другу.Первый ехал со скоростью 15км/ч, а второй проехал до встречи на 6 км больше,чем первый.С какой скоростью ехал второй велосепедист,если он встретился с первым через 3 ч.

Answer 1

Пусть Х - скорость 2го.
Первый проехал 15*3=45 км.
Второй на 6 км больше. 45+6=51 км
А его скорость Х=51/3
Х=17 км/ч

Answer 2

Problem Analysis

Two cyclists start riding towards each other at the same time. The first cyclist travels at a speed of 15 km/h, while the second cyclist travels 6 km further before meeting the first cyclist. The two cyclists meet after 3 hours. We need to find the speed at which the second cyclist was traveling.

Solution

Let's denote the speed of the second cyclist as v km/h.

The first cyclist travels for 3 hours at 15 km/h, covering a distance of 45 km (15 km/h * 3 h).

The second cyclist travels for 3 hours at v km/h, covering a distance of 3v km.

Given that the second cyclist travels 6 km further than the first cyclist, we can set up the equation: 45 km + 6 km = 3v km

Calculation

45 km + 6 km = 3v km 51 km = 3v km v = 51 km / 3 v = 17 km/h

Answer

The second cyclist was traveling at a speed of 17 km/h.